Show that exactly one of the numbers n, n + 2 or n + 4 is divisible by 3.
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not understanding sorry
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we applied euclids division algorithm on n and 3
a=bq+3 on putting a =n and b=3 n=3q +r 0 <r <3
n=3q...... (1)
n=3q+1..... (2)
n=3q+2...... (3)
n=3q is divisible by 3
or n+2=3q+1+2=3q+3 also divisible by 3
n+4=3q+2+4=3q+6 is also divisible by 3
hence n, n+2,n+4 are divisible by 3
a=bq+3 on putting a =n and b=3 n=3q +r 0 <r <3
n=3q...... (1)
n=3q+1..... (2)
n=3q+2...... (3)
n=3q is divisible by 3
or n+2=3q+1+2=3q+3 also divisible by 3
n+4=3q+2+4=3q+6 is also divisible by 3
hence n, n+2,n+4 are divisible by 3
aru03:
sorry my answer is in completed
a=bq+r on putting a=n and b=3 , n=bq+r 0
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