show that exactly one of the numbers n,n+2 or n+4 is divisible by 3
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Take n=3q+r
Then the possible outcomes are 0,1,2
If r is 0 then n=3q+0= 3q where n is divisible by 3
n+2=3q+0+2= 3q +2, nit divisible by 3
n+4= 3q +0+4, not divisible by 3
Proceed the following by substituting r values as 1 and 2
Then the possible outcomes are 0,1,2
If r is 0 then n=3q+0= 3q where n is divisible by 3
n+2=3q+0+2= 3q +2, nit divisible by 3
n+4= 3q +0+4, not divisible by 3
Proceed the following by substituting r values as 1 and 2
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