show that exactly one of the numbers n, n+2 or not+4
divisible by 3
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if 'n' is an even no.
let 'n' be 2
then, n=2
n+2=2+2=4
n+4=2+4=6
6 is divisible by 3
hence, if 'n' is and even number then n+4 is divisible by 3.
if 'n' is an odd no.
let 'n' be 1
then, n=1
n+2=1+2=3
n+4=1+4=5
3 is divisible by 3
hence, if 'n' is an odd number then n+2 is divisible by 3.
hope you understand.
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