show that exactly one of the numbers n,n+2or n+4 is divisible by3
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Hii friend..
Given numbers,
n, n+2 and n+4
Put n = 1
n+2 = 1+2 = 3 is divisible by 3
n+4 = 1+4 = 5
Put n = 2
n+2 = 2+2 = 4
n+4 = 2+4 = 6 is divisible by 3
Put n = 3 is divisible by 3
n+2 = 3+2 = 5
n+4 = 3+4 = 7
Therefore, one and only one out of n, n+2 and n+4 is divisible by 3
Hence proved!
Given numbers,
n, n+2 and n+4
Put n = 1
n+2 = 1+2 = 3 is divisible by 3
n+4 = 1+4 = 5
Put n = 2
n+2 = 2+2 = 4
n+4 = 2+4 = 6 is divisible by 3
Put n = 3 is divisible by 3
n+2 = 3+2 = 5
n+4 = 3+4 = 7
Therefore, one and only one out of n, n+2 and n+4 is divisible by 3
Hence proved!
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