Question

show that f(t)=1-sin(t) defines a smooth flow on the manifold s={(cost,sint)} but g(t)=t-sint does not.​

Answer 1

Answer:

cost, sint) but 2. Show that f(t)=1-sint defines a smooth flow on the manifold S = 8(t)=1-sint does not

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Answer 2

Step-by-step explanation:

Cost, sint) but 2 shows that ( f) =1 - sint defines a smooth flow on the manifold S= 8 (+) = 1 - sint does not