Question

show that .......

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Answer 1

SOLUTION

Assum, 3x= 2x+x

=) tan(3x)= tan (2x+x)

=) tan(3x)=

$\frac{tan(2x) + tan(x)}{1 - tan(2x)tan(x)}$

=) tan(3x) {1-tan(2x)tan(x)} = tan(2x)+tan(x)

=) tan(3x) -tan(3x) tan(2x)tan(x)= tan(2x) +tan(x)

=)tan(3x)-tan(2x) -tan(x) = tan(x) tan(2x) tan(3x)

Proved

hope it helps ✔️

Answer 2

Answer:

solutions is attached above ....