Question

show that following are irrational:2√2​

Answer 1

Step-by-step explanation:

$Let \: us \: assume \: that \: 2 \sqrt{2} \: is \: irrational \: \\ 2 \sqrt{2} = \frac{a}{b} \: where \: b \: is \: not \: equal \: to \: 0 \: and \: a \: and \: b \: are \: co \: prime \\ \: \\ \sqrt{2} = \frac{a}{2b} \\ here \: \frac{a}{2b} \: is \: rational \: but \: 2 \sqrt{2} \: is \: irrational. \\ 2 \sqrt{2} \: is \: irrational.$

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