Question

Show that for a
car, moving with constant acceleration for a
period of time, the distance travelled in the
second half is three times of that in the first
half.

Answer 1

s(distance)=ut+1/2at^2
let car starts from rest therefore u =0
for first half s=1/2a(t/2)^2=1/8at^2
for 2nd half u=at/2
so s=(at/2)*t/2+1/2a(t/2)^2
=at^2/4+at^2/8=3at^2/8
hence S at 2nd half(3at^2/8) is 3 times then S at first half(at^2/8).......
answerrrrr

Answer 2

Answer:

Here is your answer

Explanation:

Attachment