Show that for any sets A and B,
A = (A ∩ B) ∪ (A – B) and A ∪ (B – A) = (A ∪ B)
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Answer:
(¡) Let A and B be two sets
Now,
A
=A∩U
=A∩(BUB')
=(A∩B) U(A∩B')
=(A∩B) U(A-B) [since P∩Q'=P-Q]
(¡¡)
AU(B-A)
=AU(B∩A') [ since P∩Q'=P-Q]
=(AUB)∩(AUA')
=(AUB)∩ U [since PUP'=U]
=(AUB)
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