Question

Show that for first order reaction, t
87.5%= 3t50%

Answer 1

Dear Student,

For a first order reaction, we know that :

ln[A][Ao] = −kt(a)When 87.5% of initial reactant is converted, remaining [A] = 1 − 0.875 = 0.125 [Ao]Thus,ln 0.125[Ao][Ao]=−kt−kt = −2.079t87.5=2.079k −−1(b) When 50% of initial reactant is converted, remaining [A] = 1 − 0.5 = 0.5[Ao]Thus,ln 0.5[Ao][Ao]=−kt−kt = −0.693t50=0.693kMultiplying this by 3,we get 3t50 = 0.693k ×3 = 2.079k −−2Thus, 1=2So t87.5 = 3t50

Explanation:

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Answer 2

• Explanation:

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