Question

Show that for the curve rcos ( sqrt a^ 2 -b^ 2 a ) theta= sqrt a^ 2 -b^ 2 ,p^ 2 (r^ 2 +b^ 2 )=a^ 2 r^ 2 .​

Answer 1

Answer:

Show that for the curve rcos ( sqrt a^ 2 -b^ 2 a ) theta= sqrt a^ 2 -b^ 2 ,p^ 2 (r^ 2 +b^ 2 )=a^ 2 r^ 2 .