Math, asked by prashu9598, 4 months ago

Show that for the curve x = a cos t (1+sin t), y = a sin t (1+cos t), the radius of curvature is a, at the point for which the value of the parameter 0 is –pie/4​

Answers

Answered by stuchitharth4911
0

Answer:

Curvature and Radius of Curvature

Consider a plane curve defined by the equation

y

=

f

(

x

)

.

Suppose that the tangent line is drawn to the curve at a point

M

(

x

,

y

)

.

The tangent forms an angle

α

with the horizontal axis (Figure

1

).

Definition of the curvature of a plane curve

Figure 1.

At the displacement

Δ

s

along the arc of the curve, the point

M

moves to the point

M

1

.

The position of the tangent line also changes: the angle of inclination of the tangent to the positive

x

axis

at the point

M

1

will be

α

+

Δ

α

.

Thus, as the point moves by the distance

Δ

s

,

the tangent rotates by the angle

Δ

α

.

(The angle

α

is supposed to be increasing when rotating counterclockwise.)

The absolute value of the ratio

Δ

α

Δ

s

is called the mean curvature of the arc

M

M

1

.

In the limit as

Δ

s

0

,

we obtain the curvature of the curve at the point

M

:

K

=

lim

Δ

s

0

Δ

α

Δ

s

.

From this definition it follows that the curvature at a point of a curve characterizes the speed of rotation of the tangent of the curve at this point.

For a plane curve given by the equation

y

=

f

(

x

)

,

the curvature at a point

M

(

x

,

y

)

is expressed in terms of the first and second derivatives of the function

f

(

x

)

by the formula

K

=

|

y

(

x

)

|

[

1

+

(

y

(

x

)

)

2

]

3

2

.

If a curve is defined in parametric form by the equations

x

=

x

(

t

)

,

y

=

y

(

t

)

,

then its curvature at any point

M

(

x

,

y

)

is given by

K

=

|

x

y

y

x

|

[

(

x

)

2

+

(

y

)

2

]

3

2

.

If a curve is given by the polar equation

r

=

r

(

θ

)

,

the curvature is calculated by the formula

K

=

r

2

+

2

(

r

)

2

r

r

[

r

2

+

(

r

)

2

]

3

2

.

The radius of curvature of a curve at a point

M

(

x

,

y

)

is called the inverse of the curvature

K

of the curve at this point:

R

=

1

K

.

Hence for plane curves given by the explicit equation

y

=

f

(

x

)

,

the radius of curvature at a point

M

(

x

,

y

)

is given by the following expression:

R

=

[

1

+

(

y

(

x

)

)

2

]

3

2

|

y

(

x

)

|

.

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