Question

show that function f(x) = x^3 + 10x + 7 for x belong to R strictly increasing​

Answer 1

Answer:

Differentiate w r t x, we get

f'(x) = 3x^2 + 10 > 0 for every real value of x

hence f(x) is always strictly increasing

Answer 2

step by step Explanation :-

Given :- F(x) = x³+10x+7

• F'(x) = 3x² + 10 + 0
• F'(x) = 3x² + 10

★ For function to be increasing f'(x) must be >0

• 3x² + 10 >0∀x∈R

Hence, F(x) is stictly increasing on R .

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