Show that ½ gt2 has the dimension of length
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Answer:
½ gt²
here , g is acceleration due to gravity and t is time
now,
as we know numbers are dimensionless so we have to find the dimensions of gt²
[g][t²]
= [ MT^-2][ T²]
= [ MT² ` ² ]
= [MT⁰]
= [M]
which is the dimension of length.
hence proved..
Explanation:
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