show that how would you join three resistors of each resistance 6 ohm to that equivalent resistance of the combination is (1). 9 ohm (2). ohm
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1
Answer:
(0 Two resistors in parallel and then one is series 1/R=1/R1+1/R2=1/9+1/9=2/9/2 R=9/2=4.5Ω R'=R+R3 =4.5+9=13.5Ω (ii) Two resistors in series and one in Parallel R=R1+R2=9+9=18Ω 1/R'=1/R+1/R0=1/18+1/9=1+2/18=3/18 R'=18/3=6Ω Read more on Sarthaks.com - https://www.sarthaks.com/83493/show-would-join-three-resistors-each-resistance-that-equivalent-resistance-combination
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Answer:
Resistance of each resistor R=9Ω
Two resistor connected across A and B are connected in parallel.
Equivalent resistance across A and B R
AB
=
R+R
R×R
=
2
R
=
2
9
=4.5Ω
This equivalent resistance is connected in series to another resistor R.
So equivalent resistance across A and C R
AC
=R
AB
+R=4.5+9=13.5Ω
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