Question

show that i^10+i^20+i^30+i^40 is a real number​

Answer 1

Answer:

Hey friend your answer is in the attachment

Answer 2

Step-by-step explanation:

Since i^2 = - 1

Now

i^10+i^20+i^30+i^40

=( i^2)^5+(i^2)^10+(i^2)^15+(i^2)^20

=( - 1 )^5+( - 1 )^10+( - 1 )^15+( - 1 )^20

= 1 + 1 + 1 + 1

= 4

Which is a real number

Hence i^10+i^20+i^30+i^40 is a real number

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