Question

Show that : i) (2x + 1) 2 – 8x = (2x - 1) ^2

Answer 1

Answer:

$(2x - 1)2 - 8x = {(2x - 1)}^{2} \\ 4x - 2 - 8x = 4 {x}^{2} + 1 - 4x \\ 4 {x}^{2} + 3 = 0$

Answer 2

Answer:

x=√1/4

Step-by-step explanation:

4x+2-8x=(2x)^2+(1)^2-2(2x*1)

2-4x=4x^2+1-4x

2-4x+4x=4x^2+1

2-1=4x^2

1=4x^2

x=√1/4