Show that, i + e = A + 8 in case of deviation through the prism
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Derivation of prism formula
μ=sinisinr (by Snell’s law)
δ=i1−r1+i2−r2… (eq.1)
δ=i1+i2−(r1+r2) ∠ALO+∠AMO=2rt∠s (from quadrilateral and ∠ALO=∠AMO=90°)
∠LAM+∠LOM=2rt∠s (sum of four ∠s of a quadrilateral = 4 rt∠s) (eq.2)
∠r1+∠r2+∠LOM=2rt∠s (eq.3)
∠LAM=∠r1+∠r2 (comparing eq.2 and eq.3)
A=∠r1+∠r2 δ=i1+i2−A (substituting A in eq.1)
i1+i2=A+δ ∠i1=∠i2 ∠r1=∠r2=∠r ∠ALM=∠LMA=90∘−∠r
Thus, AL = LM and LM ∥ BC
∠A=∠r1+∠r2 A=2r (since, ∠r1=∠r2=∠r)
r=A2 i1+i2=A+δ i1+i1=A+δm 2i1=A+δm i1=A+δm2 ∴μ=sinA+δm2sinA2
Thus, above is the prism formula.
Explanation:
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