Question

show that i + i^2 + i^3 + i^4 = 0

Answer 1

Heya user,

i = √-1
=> i² = -1 
=> i³ = -√-1 = -i
=> i⁴ = 1

And hence,
i + i² + i³ + i⁴ = i - 1 - i + 1 = ( i - i ) + ( 1 - 1 ) = 0;