Question

show that √i+√-i is equal to√2​

Answer 1

Step-by-step explanation:

z=(a+bi) be a complex number which is a square root of i, that is i=z2=(a2−b2)+2abi.Equating real and imaginary parts we have,a2−b2=0,2ab=1

The two real solutions to this pair of equations are a=1√2,b=1√2 and a=−1√2,b=−1√2.

Sq root of i is =+/-(1+i)/root2

Si.ilarly can be found for - i