Question

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Answer 1

Answer:

Question:-

$\tt \large {( { \frac{1}{2} }^{2} })^{3} \times { \frac{1}{3} }^{ - 4} \times {3}^{ - 2} \times \frac{1}{6} = \frac{3}{128}$

Solution:-

$= \tt \large {( { \frac{1}{2} }^{2} })^{3} \times { \frac{1}{3} }^{ - 4} \times {3}^{ - 2} \times \frac{1}{6} \\ \tt = { \frac{1}{2} }^{6} \times {3}^{4} \times {3}^{ - 2} \times \frac{1}{6} \\ \tt = \frac{1}{64} \times( {3})^{4 + ( - 2)} \times \frac{1}{6} \\ \tt = \frac{1}{64} \times( {3})^{4 - 2} \times \frac{1}{6} \\ \tt = \frac{1}{64} \times {3}^{2} \times \frac{1}{6} \\ \tt = \frac{1}{64 } \times 9 \times \frac{1}{6} \\ \tt = \red{ \frac{3}{128}}$

So,L.H.S. =R.H.S.