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(i) (x + 1) is a factor of x - x - 10x - 8.
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Answered by
1
Answer:
x+1= 0
x= -1
p(x) = x³-x²-10x-8
p(-1)= (-1)³-(-1)²-10(-1)-8
= -1-1 +10-8 = -2+2=0
therefore (x+1) is a factor of x³-x²-10x-8
Answered by
0
Answer:
no (x+1) is not a factor of given equation
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