Question

Show that if 2a²+b²=(a+b)²,then a=b​

Answer 1

(a+b)²= (a^2)+(b^2)+2ab

Now (a^2)+(b^2)+2ab=2a^2 + b^2

[(a^2)+(b^2)]-[2a^2 + b^2]=0-2ab

a^2 + b^2 - 2a^2.-b^2=-2ab

a^2-2a^2+b^2-b^2=-2ab

-2a^2+0=-2ab

-2a^2=-2ab

2a^2=2ab

a^2=ab

a=b

Hope this helps you.Please mark this the brainliest

Answer 2

Answer:

I guess you got the wrong question, i am solving the answer to prove a=2b

GIven equation:

2a²+b²=(a+b)²

To prove a=2b

RHS:

(a+b)²= a²+b²+2ab

equating LHS and RHS

2a²+b²= a²+b²+2ab

a²=2ab {b² canceled both LHS and RHS,}

diving LHS and RHS both by a, we get

a=2b

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Hope it solved!!

Guess your question was wrong because a≠b (a can never be equal to b)