Question

Show that if a body is taken to a height H above the earth's surface acceleration due to gravity is decreased by the factor R2/(R +H ) square where R is the radius of the earth.

Answer 1

here is ur ans
we know that acceleration due to gravity of earth is
g = GM/ R^2
now at height H above surface of earth acceleration due to gravity must be
g' = GM/(R+H)^2
now divide both
g'/g = R^2/(R+H)^ 2
g' = g(R)^2 / (R+H)^2