show that
if sec+tan=m
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See i m not writing theta, or else it will be too much to type
Step-by-step explanation:
sec + tan = m
To prove,
m²-1/(m²+1) = sin
m²= sec²+2sectan+tan²
Now, sec²= 1+tan²
Replace it over here,
1+ 2tan² + 2sectan
m²-1= 2tan²+2sectan
m²+1 is 2+ 2tan²+ 2sectan
2 is a common factor, on division it gets cancelled out.
Now, we have
tan(sec+tan)/sec(sec+ tan)
I can write this because 1+tan²= sec²
Cancel out sec+tan
We have tan/sec or (sin/cos)/(1/cos)
cos goes up, we are it gets cancelled out, we are left with sin.
Hence proved
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