Question

Show that if the diagonal of a quadrilateral bisect each other at right angle,then it is a shombas
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Answer 1

Correct Question:-

☞ Show that if the diagonal of a parallelogram bisect each other at right angle,then it is a Rhombus .

[ For answer refer to the attachment : ]

More to know:-

Also have a look at the properties of a parallelogram.

• Opposite sides are parallel.
• Opposite angles are equal .
• Sum of adjacent angles is 180°.
• Diagonals bisect each other.
• Parallelogram on same base and between same parallels are equal.

Remember :-

All parallelograms are quadrilaterals , but all quadrilaterals are not parallelogram.

Answer 2

Step-by-step explanation:

Take quadrilateral ABCD , AC and BD are diagonals which intersect at O.

In △AOB and △AOD

DO=OB ∣ O is the midpoint

AO=AO ∣ Common side

∠AOB=∠AOD ∣ Right angle

So, △AOB≅△AOD

So, AB=AD

Similarly, AB=BC=CD=AD can be proved which means that ABCD is a rhombus.