show that if the diagonals of a a quadrilaterals bisect each other at right angle then to is a rhombus
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Step-by-step explanation:
Given:- let ABCD be a quadrilateral
where diagonal bisect each other
.
. .OA=OC, .....(1)
and
OB=OD, .....(2)
and they bisect at right angles
So, <AOB = <BOC =<COD=<AOD = 90° .....
To prove : ABCD a rhombus,
proof : rhombus is parallelogram with all sides equal we first prove ABCD is a parallelogram and then prove all the side of ABCD are equal
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hope this will help you..
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