show that if the diagonals of a quadrilateral bisect each other at a right angles,then it is a rhombus
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in quadrilateral ABCD,
AC and BD are diagonals which intersect at O.
in triangle AOB and triangle AOD,
DO=OB( O is the mid point)
AO is the common side
angle AOB= angle AOD(right angle)
therefore, triangle AOB is congruence to triangle AOD
AB=AD
similarly, AB=BC=CD=AD can be proved which means
that ABCD is a rhombus.
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