Show that if the diagonals of a quadrilateral bisect each other at right angles, then it is a rhombus
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the angles is 360 degree
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We have a quadrilateral ABCD such that the diagonals AC and BD bisect each other at right angles at O.
∴ In ΔAOB and ΔAOD, we have
AO = AO [Common]
OB = OD [Given that O in the mid-point of BD]
∠AOB = ∠AOD [Each = 90°]
ΔAOB ≌ ΔAOD [SAS criteria]
Their corresponding parts are equal.
AB = AD...(1)
Similarly,
AB = BC...(2)
BC = CD...(3)
CD = AD...(4)
From (1), (2), (3) and (4), we have
AB = BC
CD = DA
Thus, the quadrilateral ABCD is a rhombus.
Hope it helps.
Mark Brainer.
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