show that if the three digit number in the form of 906 that is digit at tens place in zero is subtracted from the sum of its digits we always get a number divisible by 11.
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show that, if the 3 digit number in the form of 906 (i.e. digit at tens place is 0) is subtracted from the sum of its digits, we always get a number divisible by 11. the number is 906. now if we divide 891 by 11, we get 81 as the answer.
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