Question

Show that if the velocity of the body increase to ' n ' times, then the stopping distance increases to n square times for uniform acceleration?

Answer 1

Answer:

mark as Brainliest

Explanation:

Given:

Acceleration is uniform.

Velocity increases by n times.

To find:

Factor by which stopping distance increases

Step-by-step explanation:

Equation of motion is: v^{2} = u^{2} + 2asv

2

=u

2

+2as

u = 0

Now,

Initially, v^{2} = 2asv

2

=2as ...........(1)

Finale, when velocity increases n times.

(nv)^{2} = 2as'(nv)

2

=2as

′

.............(2)

Acceleration will be the same in 1 and 2 because acceleration is uniform.

Dividing equation 1 and 2 we get,

s' = n^{2} ss

′

=n

2

s

Hence, proved that when the velocity of a body in uniform motion increases by nn time, then the stopping distance increases by n^{2}n

2

times.

Answer 2

Answer:

answer will be text the photos

Explanation:

Mark me as brainlist plzz follow me