show that in a right angled triangle the hypotenuse is the longest side
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In a right angled triangle, the angle opposite To the hypotenuse is 90°, while other two angles are Always less than 90°. As you know that the side opposite to the largest angle is always the largest in a triangle.
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Let ABC be an isosceles triangle with AB = AC.
Draw the bisector AD of A which meets BC in D.
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In ∆ABD and ∆ACD, we have
- AB = AC
- BAD = CAD
- AD = AD
1st was given
2nd was (AD is bisector of A)
3nd was common.
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So, by SAS-CRITERION of congruence, we have
∆ABD ∆ACD.
C = B.
The converse of the above is true i.e., if two angles of a triangle are equal, then the opposite to them are also equal.
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