Question

Show that in an isosceles triangle angle opposite ti equal side are equal

Answer 1

Answer:Abc is a isosceles triangle than ab = bc. -Eq 1

90 degree at b

Then by applying phytogouras theorem

(ac)*2 = (ab)*2 + (bc)*2

(ac)*2 =(ab)*2 + (ab)*2

(ac)*2 =2(ab)*2

Step-by-step explanation:

Answer 2

✯✯ QUESTION ✯✯

Show that in an iscocles triangle opposite to equal sides,are equal.

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✰✰ ANSWER ✰✰

→Consider an iscoceles triangle ABC in which AB=AC...

⠀⠀⠀⠀⠀(Refer to the attachment)

➮To Prove : -

$\implies\tt{\angle{B}=\angle{C}}$

➮Construction : -

Draw an perpendicular AB to BC , AD ⊥ BC..

➥Now ,

In Δ ABD and Δ ACD : -

$\implies\tt{AB=AC}$ (Given)

$\implies\tt{\angle{ADB}=\angle{ADC}}$ (Each 90°)

$\implies\tt{AD=AD}$ (Common)

➮So , SAS (Side Angle Side ) rule ΔABD ≅ ΔACD....

➥And ,

$\implies\tt{\angle{B}=\angle{C}}$ (By CPCT rule)

✺ HENCE PROVED ✺

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★SAS Rule : -

Two Triangles are congruent if two sides and the included angle of one triangle are equal to the sides and included angle of other traingles..

★CPCT : -

Corresponding Parts of Congruent Triangles..

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