show that in an isosceles triangle,angle opposite to equal sides are equal
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Step-by-step explanation:
attatchment below
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Answered by
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Step-by-step explanation:
Given:Isosceles triangle ABC
i.e., AB=AC
To prove:∠B=∠C
Construction:Draw a bisector of ∠A intersecting BC at D.
Proof:In △BAD and △CAD
AB=AC(given)
∠BAD=∠CAD by construction
AD=AD(common)
∴△BAD≅△CAD by SAS congruence rule.
Thus, ∠ABD=∠ACD by CPCT
⇒∠B=∠C
Hence, angles opposite to equal sides are equal.
Hence proved.
Hope my explanation helps u.
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