Question

Show that in an isosceles triangle , angles opposite to equal sides are equal.​

Answer 1

in the figure

AB= AC

and AD is the bisector of <A

In ∆ADC & ∆ADB

AB=AC(S)

<CAD=<BAD(A)

AD=AD(S)

By S. A. S

∆ADC is congruent to ∆ADB

If two triangles are congruent then, there corresponding parts are also equal. So, <B=<C

that means, angles opposite to equal sides of a isosceles triangle are equal

I hope my answer helps you ☺☺