show that in an isosceles triangle angles opposite to equal sides are equal
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Step-by-step explanation:
Let D be the point of intersection of this bisector of ∠A and BC. Therefore ,by construction ∠BAD = ∠CAD. So, ∠ABD = ∠ACD, since they are corresponding angles of congruent triangles. Hence, Proved that an angle opposite to equal sides of an isosceles triangle is equal.15-
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Here we will prove that in an isosceles triangle, the angles opposite to the equal sides are equal. Given: In the isosceles ∆XYZ, XY = XZ. To prove ∠XYZ = ∠XZY. Construction: Draw a line XM such that it bisects ∠YXZ and meets the side YZ at M.
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