Math, asked by durga124, 17 hours ago

show that in an isosceles triangle angles opposite to equal sides are equal
in pictures​

Answers

Answered by llchummill
0

Step-by-step explanation:

Let D be the point of intersection of this bisector of ∠A and BC. Therefore ,by construction ∠BAD = ∠CAD. So, ∠ABD = ∠ACD, since they are corresponding angles of congruent triangles. Hence, Proved that an angle opposite to equal sides of an isosceles triangle is equal.15-

Answered by yogeshindia
0

Answer:

Here we will prove that in an isosceles triangle, the angles opposite to the equal sides are equal. Given: In the isosceles ∆XYZ, XY = XZ. To prove ∠XYZ = ∠XZY. Construction: Draw a line XM such that it bisects ∠YXZ and meets the side YZ at M.

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