show that in an isosceles triangle, opposite side are e
qual
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Answered by
1
Answer:
Let △ABC be an isosceles triangle such that AB =AC Then we have to prove that ∠B=∠C Draw the bisector AD of ∠A meeting BC in D
Now in triangles ABD and ACD We have AB=AC (Given)
∠BAD=∠CAD (because AD is bisector of ∠A
AD=AD (Common side)
Therefore by SAS congruence condition we have
△ABC≅△ACD
⇒∠B=∠C
(Corresponding parts of congruent triangles are equal )
hope it helps
Answered by
2
Answer:
Let △ABC be an isosceles triangle such that AB =AC Then we have to prove that ∠B=∠C Draw the bisector AD of ∠A meeting BC in D
Now in triangles ABD and ACD We have AB=AC (Given)
∠BAD=∠CAD (because AD is bisector of ∠A
AD=AD (Common side)
Therefore by SAS congruence condition we have
△ABC≅△ACD
⇒∠B=∠C
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