Show that in an isosceles triangle, the angle opposite to equal sides
are equal. (Hint: Draw perpendicular bisector of unequal side)
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Visualisation:
Draw a ∆ABC
Answer:
Given:ABC is an isosceles triangle i.e., AB=AC
To prove: Angles opposite to equal sides are equal i.e.,B=C
Construction: Draw a median AD to the side BC of ∆ABC.
Consider ∆ABD and ∆ACD,
AB=AC (Given)
AD=DA (Common)
BD=CD (Construction)
By SSS congruency rule,
∆ACD is congruent to ∆ABD
By CPCT,
B=C
Thus,angles opposite to equal sides are equal
Hence,proved
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Answered by
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angles opposite to equal
hence proved
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