Question

Show that in an isosceles triangle, the angle opposite to the equal sides are equal.

Answer 1

Answer:

Here we will prove that in an isosceles triangle, the angles opposite to the equal sides are equal. Given: In the isosceles ∆XYZ, XY = XZ. To prove ∠XYZ = ∠XZY.

I hope this answer helps you

thank you

(please follow me guys)

Answer 2

Answer:

Let ABC be an isosceles triangle in which AB = AC

then, we have to prove that ∠B =∠C

Draw AD, the bisector of ∠BAC and let it meet BC in D

Now, in ∆BAD and ∆CAD, we have

AB = AC

∠BAD = ∠CAD

AD = AF

∆BAD = ∆CAD

∠B = ∠C