Question

show that in an isosceles triangle the angles opposite the equal sides are equal. draw a perpendicular to the unequal side from the vertex​

Answer 1

$\Huge{\underline{\underline{\blue{\mathfrak{ Solution :- }}}}}$

$\sf Given :-\\\\\Isoceles\ Triangle\ ABC\\i.e.\ AB = AC\\\\\\\\To\ prove :-\\\\\angle B = \angle C\\\\\\\\Construction :-\\\\Draw\ a\ bisector\ of\ \angle A\ intersecting\ BC\ at\ D.\\\\\\\\Proof :-\\\\\In\ \triangle\ BAD\ and\ \triangle\ CAD\\\\\\AB = AC\ (Given)\\\\\angle BAD = \angle CAD\ (By\ construction)\\\\AD = AD\ (Common)\\\\\triangle BAD\ is\ congruent\ to\ \triangle CAD (By\ SAS\ congruence\ rule)\\\\\\\\Thus,\\\\ \angle ABD = \angle ACD\ (By\ CPCT)\\\\ \angle B = \angle C\\ Hence,\ proved.$

Answer 2

Answer:

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