Show that in an isosceles triangle,the angles opposite the equal sides are equal. ( Hint: Draw a perpendicular to the unequal side from the vertex.)
Please give me the correct solution fast
Answers
Answered by
3
Answer:
Answer
Given-AB=AC
To prove-∠B=∠C
Construction-Draw AD⊥BC
Proof-In triangles ADB and ADC
AB=AC (given)
AD=AD (common)
∠ADB=∠ADC (90
o
)
Then by RHS criteria we have triangle ADB ≅ triangle ADC
Hence, by c.p.c.t ∠B=∠C
solution
Answered by
2
Attachments:
Similar questions