Question

show that in any triangle ABC that tan A-B-C/2=-cotA​

Answer 1

Answer:

for a triangle the sum of three angles are 180°

Step-by-step explanation:

now see.....

tan(A-B-C) /2

=tan(A-180+A)/2

=tan(2A-180)/2

=tan(A-90)

=tan [-(90+A)]

=cot(-A)

=-cot A

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