Question

show that in SI units, the unit of G is Newton m²kg–². the value of G was first experimentally measured by Henry Cavendish.In SI units its value is 6.673X10–¹¹Nm²kg–².

Answer 1

This is answer (underlined)

Answer 2

The SI unit of G is $G=Nm^2/kg^2$

Explanation:

Newton's law of universal gravitation states that the force acting between two masses is directly proportional to the product of masses and inversely proportional to the square of distance between them. The force is given by :

$F=G\dfrac{m_1m_2}{d^2}$

G is universal gravitational constant

$G=\dfrac{Fd^2}{m_1m_2}$

Writing in terms of SI unit :

$G=\dfrac{N-m^2}{kg^2}$

or

$G=Nm^2/kg^2$

The value of G was first experimentally measured by Henry Cavendish. Its value is $G=6.673\times 10^{-11}\ Nm^2/kg^2$.

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Universal law of gravitation

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