show that in single throw of two dice , the probability of throwing more than 7 is equal to that of throwing less than 7 and hence find the probability of throwing exactly 7. state clearly what assumption you are making.
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SOLUTION: Show that in a single throw of two dice, the probability of throwing more than 7 is equal to that of throwing less than 7, and hence find the probability of exactly 7. throwing less than 7, and hence find the probability of exactly 7. That leaves a 6/36=1/6 probability for a sum of 7.
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