Show that in the absence of any external force the velocity of center of mass remains constant
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Force = rate of change of momentum
Thus when f is zero (i.e.) external force is zero
0=mv-mu/t
0=d(mv) / dt
since m is constant
0=m(dv/dt)
0=dv/dt #
it is constant
Thus when f is zero (i.e.) external force is zero
0=mv-mu/t
0=d(mv) / dt
since m is constant
0=m(dv/dt)
0=dv/dt #
it is constant
Answered by
1
Hello there,
Before going to the answer some points are to be considered.
1.force =rate of change of momentum=d(p)/d(t).
2. If an no external force is present, F=0.
3.the fact that mass ≠0.
Coming to the answer.....
F=d(p)/d(t).
We know that p=mv. Where m is mass nd v is velocity.
So F=d(mv)/d(t).
F=m d(v)/d(t).
Since there is no force ,f=0.
So m d(v)/d(t)=0
Mass can never be zero so
So this itself is a self explanatory fact that velocity tends to be constant in such cases.
I hope this helps u .....nd doubts are indeed welcome
Before going to the answer some points are to be considered.
1.force =rate of change of momentum=d(p)/d(t).
2. If an no external force is present, F=0.
3.the fact that mass ≠0.
Coming to the answer.....
F=d(p)/d(t).
We know that p=mv. Where m is mass nd v is velocity.
So F=d(mv)/d(t).
F=m d(v)/d(t).
Since there is no force ,f=0.
So m d(v)/d(t)=0
Mass can never be zero so
So this itself is a self explanatory fact that velocity tends to be constant in such cases.
I hope this helps u .....nd doubts are indeed welcome
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