Show that in the quadrilcateral ABCD AB+BC+CD+DA is greater than AC+BD
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ABCD is a quad.Its diagonals are AC and BD.
In triangle ACB, AB + BC > AC - 1
In triangle BDC, BC + CD > BD - 2
In triangle ACD, AD + DC > AC -3
In triangle BAD, AB + AD > BD -4
Adding 1,2,3 and 4,
AB + BC + BC + CD + AD + DC + AB + AD > AC + BD + AC + BD
2AB + 2BC + 2CD + 2AD > 2AC + 2BD
AB + BC + CD + AD > AC + BD.
please consider this as BRAINLIEST ANSWER
.
In triangle ACB, AB + BC > AC - 1
In triangle BDC, BC + CD > BD - 2
In triangle ACD, AD + DC > AC -3
In triangle BAD, AB + AD > BD -4
Adding 1,2,3 and 4,
AB + BC + BC + CD + AD + DC + AB + AD > AC + BD + AC + BD
2AB + 2BC + 2CD + 2AD > 2AC + 2BD
AB + BC + CD + AD > AC + BD.
please consider this as BRAINLIEST ANSWER
.
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