Math, asked by keishambudhachand, 6 months ago

show that integral of sin^6xcos^2xdx from limit 0 to pi/2=2/63​

Answers

Answered by anwarshekh600
0

Step-by-step explanation:

sin^6×cos^2×dx answer=eeror pi/2=36/2 pi/2=18 pi=18×2 pi=36 answer or pi/2=2/36 pi/2=0.0555555556 pi=0.0555555556×2 pi=0.111111111 answer

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