Question

show that is irrational

$3 \sqrt{2}$


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Answer 1

Answer:

ok

if

$3 \sqrt{2}$

is not irrational so let us suppose that it is rational

so by property of rationals numbers

$3 \sqrt{2 } = p \div q$

so

$\sqrt{2} = p \div q \times 1 \div 3$

now we know that on RHS there is rational number but on LHS there is irrational number

so our supposition is wrong

$3 \sqrt{2}$

is an irrational number

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