Show that ke=1/2mv^2 pe=mgh
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Answer:
Explanation:
let a body of mass moving with the acceleration the force acting on the body will be:
f=ma---------1
if the body is displaced from the rest position to the distance s
then,the work done in the body
w=fs---2
w=(ma)s from 1
if the final velocity of the object is v after moving the distance =
v2=u2+2as
now s=v2/2a----3
putting the value of 3rd in eq 1 we get,
w= ma * v2 /2a
w=1/2mv2
This is your answer for KE = 1/2 mv2
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Ankit1541 avatar
Ankit1541
02.03.2018
Physics
Primary School
answered
Prove potential energy (P.E) = mgh ,with figure ,
2
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AbhinavKumar1312004
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The object is placed at hieght h
Work done=Force * Displacement ..(1)
Then,
Force= mass * acceleration
Here acceleration is due to gravity
Then,
Force = M * g ......(2)
From (1) and (2)
Work done= M * g * displacement ..(3)
Then,
Here displacement is h
Displacement = h ...(4)
Then ,
From (3) and (4)
Work = M*g*h
Work=Mgh
This is answer for PE= mgh