Question

show that kinetic energy and potential energy are dimensionally similiar. 5marks​

Answer 1

Answer:

Hello there!

Lets see what the answer would be..

We know that K.E=mv^2/2 and P.E=mgh

Where ,

m=mass

v=velocity

g=Acceleration due to gravity

h=height

So dimensionally ,

Mass, m= M

Velocity=LT^-1

Height, h=L

Acc. Due to gravity ,g=LT^-2

So, K.E=M(LT^-1)^2

=ML^2T^-2

And P.E=M(LT^-2)L

=ML^2T^-2

And its the same in both cases..

Cheers!

Answer 2

Lets see what the answer would be..

We know that K.E=mv^2/2 and P.E=mgh

Where ,

• m=mass
• v=velocity
• g=Acceleration due to gravity
• h=height

So dimensionally ,

• Mass, m= M
• Velocity=LT^-1
• Height, h=L
• Acc. Due to gravity ,g=LT^-2

So, K.E=M(LT^-1)^2

=ML^2T^-2.

And P.E=M(LT^-2)L

=ML^2T^-2

And its the same in both cases.